Y=21x^2-14x+12

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Solution for Y=21x^2-14x+12 equation: 



=21Y^2-14Y+12

We move all terms to the left:

-(21Y^2-14Y+12)=0

We get rid of parentheses

-21Y^2+14Y-12=0

a = -21; b = 14; c = -12;
Δ = b2-4ac
Δ = 142-4·(-21)·(-12)
Δ = -812
Delta is less than zero, so there is no solution for the equation

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